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SOLVED: Question 1 - Differentiability (Show Working) Let f : â„ â†' â„ be given by: f(x,y) = √(x^2 + y^2) if (x,y) ≠(0,0) f(x,y) = 0 if (x,y) = (0,0)
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To be differentiable, a function must be continuous and smooth. Derivatives will fail to exist at: cornercusp vertical tangent discontinuity. - ppt download
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SOLVED: Decide if the following function f(x) is differentiable at x=0. Try zooming in on a graphing calculator (like desmos or geogebra), or try calculating the derivative f^'(0) from the definition. f(x)={
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![AP Calculus] Using a calculator to take the derivative : r/HomeworkHelp](https://preview.redd.it/ap-calculus-using-a-calculator-to-take-the-derivative-v0-93ooh01wm74c1.png?auto=webp&s=45d189ce8293ec852aabfe7678611e8ee31a5eae "AP Calculus] Using a calculator to take the derivative : r/HomeworkHelp")
AP Calculus] Using a calculator to take the derivative : r/HomeworkHelp
